2019 WAEC PHYSICS OBJ & ESSAY QUESTIONS AND ANSWERS NOW AVAILABLE

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2019 WAEC PHYSICS OBJ & ESSAY QUESTIONS AND ANSWERS NOW AVAILABLE

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WAEC 2019 – PHYSICS ANSWERS. NOTE NO FREE ANSWERS FOR ENGLISH, SUBSCRIBE TO AVOID SETTING IN A HOT SEAT

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PHYSICS OBJ:

1-10: CBBBCACBCB

11-20: CCCABBBDCD

21-30: CCDADCDDDA

31-40: BDDBBCAABC

41-50: ABDABDBCBA

 

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(1)
Mass = 20g = (20/100)kg = 0.02kg
Extension = 5cm = (5/100)m = 0.05m
K = 200N/
V = ?
1/2mv² = 1/2ke²
V = √ke²/m = √200×0.05×0.05/0.02
V = √25
V = 5m/s
name

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(2a)
P is initial velocity in m/s
β is angle of projection
H is maximum height
R is Range

(2b)
R = P²sin2β/g
at maximum range, sin2β = 1
=> Rmax = p²/g
This happens at β = 45degree
name

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(3)
(i) Photoelectricity
(ii) Thermonic equation
(iii) Compton effect

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(4)
(i) magnetic declination
(ii) magnetic inclination
(iii) horizontal components

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(5a)

Free eletcron: These are electrons which are not attached to an atom. They are mobile electrons which are free for bonding.

 

(5b)

Holes are spaces left by electrons in an atom in a crystal lattice. They are positively charged.

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(6a)

Principle of operation of fiber optics state that the density of transparent glass and the refractive index is greater than the density of the two mirrors. It makes use of the principle of the total internal reflection.

 

(6b)

(i) It is used to view deep down the throat of a patient

(ii) It is used to conveying information

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(8)
name

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(9ai)
Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process.

(9aii)
(i)surface area in contact with atmosphere
(ii)nature of the liquid

(9bi)
The rate of absorption of heat by clay pot is less than the rate of absorption of heat by plastics. Also, water gets evaporated in a clay pot which the evaporation causes cooling; so water in a clay pot remains cool

(9bii)
An increase in pressure in the cooker increase the ambient temperature in the cooker hence the food cooks faster

(9c)
(i) Change in the state of a substance
(ii) Increase in temperature

(9di)
Heat supplied = m1
lvt = m1
12*40*1400=1.5*1
L=12*40*1400/1.5
L=672000/1.5= 448,000J/kg
Laten heat of fusion of the body = 4.48*10^5J/Kg

(9dii)
lvt=mc D tita
12*40*72=1.5*c*60
C=12*40*72/1.5*60
C=384J/Kg/K
Specific heat capacity of the body =384J/Kg/K

 

(9)
name

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(11)
name</i.<>

 

 

 

 

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2019 WAEC PHYSICS OBJ & ESSAY QUESTIONS AND ANSWERS NOW AVAILABLE

2019 WAEC PHYSICS OBJ & ESSAY QUESTIONS AND ANSWERS NOW AVAILABLE

2019 WAEC PHYSICS OBJ & ESSAY QUESTIONS AND ANSWERS NOW AVAILABLE

2019 WAEC PHYSICS OBJ & ESSAY QUESTIONS AND ANSWERS NOW AVAILABLE

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